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X=\frac{6±\sqrt{6^{2}4\times 3\left(1y\right)}}{2\times 3} This equation is in standard form ax^{2}bxc=0 Substitute 3 for a, 6 for b, and 1y for c in the quadratic formula, \frac{Y = 2x− 5 y = 2 x 5 Use the slopeintercept form to find the slope and yintercept Tap for more steps Slope 2 2 yintercept (0,−5) ( 0, 5) Any line can be graphed using two points Select
Formula for love X^2(ysqrt(x^2))^2=1 (wolframalphacom) 2 points by carusen on hide past favorite 41 comments ck2 on0 I like all the answers gone before me However, just to add another different (if not longer method) We start by dividing through by x first we find y x y ′ 1 = 1 ( y x) 2 then subbing in v = y x we obtain v ( x v ′ v) 1 = 1 v 2 rearrange we obtain ∫ v 1 v 2 − 1 v 2 d v = − ∫ 1 x d xFactor (xy)^2 (xy)^2 (x y)2 − (x − y)2 ( x y) 2 ( x y) 2 Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (ab)(a−b) a 2 b 2 = ( a b) ( a b) where a = x y a = x y and b = x−y b = x y
Solved Solve The Following Differential Equations X Y 3 Dx X Y 1 Dy 0 2 X Y 1 Dx 3x 4y 2 Dy C 3 1 Y 2 Xy 2 Dx X 2y Y 2xy Dy Course Hero
