Formula for love X^2(ysqrt(x^2))^2=1 (wolframalphacom) 2 points by carusen on hide past favorite 41 comments ck2 on0 I like all the answers gone before me However, just to add another different (if not longer method) We start by dividing through by x first we find y x y ′ 1 = 1 ( y x) 2 then subbing in v = y x we obtain v ( x v ′ v) 1 = 1 v 2 rearrange we obtain ∫ v 1 v 2 − 1 v 2 d v = − ∫ 1 x d xFactor (xy)^2 (xy)^2 (x y)2 − (x − y)2 ( x y) 2 ( x y) 2 Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (ab)(a−b) a 2 b 2 = ( a b) ( a b) where a = x y a = x y and b = x−y b = x y
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(x-y)(x^2+xy+y^2) formula
(x-y)(x^2+xy+y^2) formula-Sin (x)cos (y)=05 2x−3y=1 cos (x^2)=y (x−3) (x3)=y^2 y=x^2 If you don't include an equals sign, it will assume you mean " =0 " It has not been well tested, so have fun with it, but don't trust it If it gives you problems, let me know Note it may take a few seconds to finish, because it has to do lots of calculations(x−a) 2 (y−b) 2 = r 2
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That is the formula of x2y2= (xy)(xy) An equilateral triangle has side lengths of 62 inches and angle measures of 60 degrees Another way of deriving this formula is as follows (the thinking here is important for understanding how we develop the later formulas in this section) If we add all these typical rectangles, starting from `a` and finishing at `b`, the area is approximately `sum_(x=a)^b(y_2y_1)Delta x`Set y y equal to the new right side y = x 2 y = x 2 y = x 2 y = x 2 Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k k a = 1 a = 1 h = 0 h = 0 k = 0 k = 0 Since the value of a a is positive, the parabola opens up Opens Up
Piece of cake Unlock StepbyStep y=x^2 Extended Keyboard ExamplesFactor x^2y^2 x2 − y2 x 2 y 2 Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (ab)(a−b) a 2 b 2 = ( a b) ( a b) where a = x a = x and b = y b = yA first order Differential Equation is Homogeneous when it can be in this form dy dx = F ( y x ) We can solve it using Separation of Variables but first we create a new variable v = y x v = y x which is also y = vx And dy dx = d (vx) dx = v dx dx x dv dx (by the Product Rule) Which can be simplified to dy dx = v x dv dx
Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicSolution for dy X Y 2) Solve the differential equation dx Q The ball dropped from a height of 10 meters bounces 2/3 of the previous one in each bounceWhat is A Total distance traveled by the ball;For example, 3 × 5 is a factorization of the integer 15, and (x – 2)(x 2) is a factorization of the polynomial x 2 – 4 Factorization is not usually considered meaningful within number systems possessing division , such as the real or complex numbers , since any x {\displaystyle x} can be trivially written as ( x y ) × ( 1 / y
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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!Asked in Class XII Maths by rahul152 (2,8 points) Solve the differential equation dy/dx = 1xy 2 xy 2, when y = 0, x = 0
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Let P(h, k) be a point on the curve y = x^2 7x 2, nearest to the line, y = 3x – 3 Then the equation of the normal to curve at P is askedAll equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction y^ {2}2xyx^ {2}=121 y 2 2 x y x 2 = 1 2 1 Subtract 121 from both sides of the equationGraph x^2y^2=1 x2 − y2 = −1 x 2 y 2 = 1 Find the standard form of the hyperbola Tap for more steps Flip the sign on each term of the equation so the term on the right side is positive − x 2 y 2 = 1 x 2 y 2 = 1 Simplify each term in the equation in order to set the right side equal to 1 1 The standard form of an
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Example 7 (y 1) 2 = x If we think about the equation (y 1) 2 = x for a while, we can see that x will be positive for all values of y (since any value squared will be positive) except y = −1 (at which point x = 0) In the equation (y 1) 2 = x, the "plus 1" in brackets has the effect of moving our rotated parabola down one unit ExampleX = −y, z = −1Find the general solution of differential equation (x^2 – yx^2) dy (y^2 xy^2) dx = 0 asked in Differential Equations by Siwani01 ( 504k points) differential equations
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"Rational Solutions to x^y = y^x" CTK Wiki Math "x^y = y^x commuting powers" Arithmetical and Analytical Puzzles Torsten Sillke Archived from the original on dborkovitz () "Parametric Graph of x^y=y^x" GeoGebra OEIS sequence A (Decimal expansion of −x, where x is the negative solution to the equation 2^xOrdinarydifferentialequationcalculator xy'y=x^{2}2x1 en Related Symbolab blog posts Advanced Math Solutions – Ordinary Differential Equations Calculator, Bernoulli ODE Last post, we learned about separable differential equations In thisExtended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music
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Add 2 2 to both sides of the equation x = 2 x = 2 x = 2 x = 2 xintercept (s) in point form xintercept (s) ( 2, 0) ( 2, 0) xintercept (s) ( 2, 0) ( 2, 0) Find the yintercept Tap for more steps To find the yintercept (s), substitute in 0 0 for x x and solve for y yIf the transformed equation of a curve is 9 x 2 1 6 y 2 = 1 4 4 when the axes rotated through an angle of 4 5 o then the original equation of a curve is View solution lf the transformed equation of a curve is 1 7 X 2 − 1 6 X Y 1 7 Y 2 = 2 2 5 when the axes are rotated through an angle 4 5 o , then the original equation of the curve is In Trigonometry Formulas, we will learnBasic Formulassin, cos tan at 0, 30, 45, 60 degreesPythagorean IdentitiesSign of sin, cos, tan in different quandrantsRadiansNegative angles (EvenOdd Identities)Value of sin, cos, tan repeats after 2πShifting angle by π/2, π, 3π/2 (CoFunction Identities or P
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The three loci of double points x = 0, y = 0, and z = 0, intersect at a triple point at the origin For example, given x = yz and y = zx, the second paraboloid is equivalent to x = y/z Then = and either y = 0 or z 2 = 1 so that z = ±1 Their two external intersections are x = y, z = 1;Equation of normal at (2,2) is y −2= 21 (x−2) ⇒ 2y−x= 2 Here , we can solve by checking options So ,option A satisfies above equation Hence (− 922Y=x^2 WolframAlpha Volume of a cylinder?
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Note General Form always has x 2 y 2 for the first two terms Going From General Form to Standard Form Now imagine we have an equation in General Form x 2 y 2 Ax By C = 0 How can we get it into Standard Form like this?All equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}yxy^ {2}=13 x 2 y x y 2 = 1 3 Subtract 13 from both sides of the equation Let's see how we can learn it 1In sin, we have sin cos In cos, we have cos cos, sin sin In tan, we have sum above, and product below 2For sin (x y), we have sign on right For sin (x – y), we have – sign on right right For cos, it becomes opposite For cos (x y), we
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By using Pythagoras you would end up with the equation given where the 4 is in fact r^2 To obtain the plot points manipulate the equation as below Given" "x^2y^2=r^2" ">" "x^2y^2 =4 Subtract x^2 from both sides giving " "y^2=4x^2 Take the square root of both sides " "y=sqrt(4x^2) Now write it as " "y=sqrt(4x^2) '~~~~~ Calculate andX^2y^2=1, (x2)^2(y1)^2=4 Natural Language;Stack Exchange network consists of 178 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack Exchange
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Suppose the curves are x = y2 and x = 4 y2 and and you want to find points on the two curves with the same yvalue Then substitute y 2 from the first equation into the second to obtain x = 4 x So to achieve the same yvalue the xvalue on the second curve must be (minus) 4 times the xvalue on the first curve x = 4y2 and x = y2Arguably, y = x^2 is the simplest of quadratic functions In this exploration, we will examine how making changes to the equation affects the graph of the function We will begin by adding a coefficient to x^2 The movie clip below animates the graph of y = nx^2 as n changes betweenIn a given equation, u(x, y) = 3qxy 2 2 and v(x, y) = x 3 y 3 Using Cauchy – Riemann Equations, find value of q Given u(x, y) = 3qxy 2 2 v(x, y) = x 3
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Take the square root of both sides of the equation x^ {2}y^ {2}z^ {2}=0 Subtract z^ {2} from both sides y^ {2}x^ {2}z^ {2}=0 Quadratic equations like this one, with an x^ {2} term but no x term, can still be solved using the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a}, once they are put in standard form ax^ {2}bxc=0 The first part checks if A1 is either X Y or Z If it's true, it returns "W", if it's false, it will call for another IF statement, that checks if A1 is in G H or J If it's true, yes, "W" again, if it's not, it'll just put nothing in there It's possible to simplify it, by using only one IF/OR like thisX 2 y 2 − 1 = x 2 / 3 y , which can easily be solved for y y = 1 2 ( x 2 / 3 ± x 4 / 3 4 ( 1 − x 2)) Now plot this, taking both branches of the square root into account You might have to numerically solve the equation x 4 / 3 4 ( 1 − x 2) = 0 in order to get the exact x interval Share
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Show that the system of the equation 3 x − y 4 z = 3, x 2 y − 3 z = − 2 and 6 x 5 y λ z = − 3 has at least one solution for any real number λ = − 5 Find the set of solution, if λ = − 5And bounces to 2/3*10 meters and#maths #mathsproblem #differentialequation #variableseprable
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The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}2yxy^ {2}=0 x 2 2 y x y 2 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 2y for b, and y^ {2} for c in the quadratic formula, \frac {b±\sqrt {b^ {2 You have x2 −y2 = (x y)(x −y) So in your case x2 − y2 x −y = (x y)(x − y) x − y = x y Answer linkPolynomial identities (short multiplication formulas) (x y) 2 = x 2 2xy y 2 (x y) 2 = x 2 2xy y 2 Example 1 If x = 10, y = 5a (10 5a) 2 = 10 2 2·10·5a (5a) 2 = 100 100a 25a 2 Example 2 if x = 10 and y is 4 (10 4) 2 = 10 2 2·10·4 4 2 = 100 80 16 = 36 The opposite is also true 25 a 4a 2 = 5 2
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The ball drops from 10 meters;X^3 x^2 y x y^2 y^3 Natural Language;This equation is in standard form ax^{2}bxc=0 Substitute 1 for a, 2 for b, and y\left(6y\right) for c in the quadratic formula, \frac{b±\sqrt{b^{2}4ac}}{2a}
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X Y x=y2 y=x2 (1,1) (4,2) Figure 2 The area between x = y2 and y = x − 2 split into two subregions If we slice the region between the two curves this way, we need to consider two different regions Where x > 1, the region's lower bound is the straight line For x < 1, however, the region's lower bound is the lower half of the
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